Example:
The events E and G are independent if P(E∩G) = P(E)P(G).
Therefore, we need to show P(E∩G) = P(E)P(G).
P(E∩G) = P({6}) = 1/6
P(E) = 1/2, P(G) = 1/3
P(E)P(G) = 1/21/3 = 1/6 = P(E∩G)
=> E and G are independent.